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Hi guys got a basket case 66 coupe, I’ve disassembled the whole front end from the firewall and needed to replace both front floor supports. The problem I’m having is trying to figure out the floor supports to the inner rocker plate is it supposed to be equal off both sides 10” ish? This car was repaired before and one side is 9” and the other was 10.5 off inner rocker. If someone could check yours or point me to a diagram that shows this measurement? Thanks
 

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This diagram doesn't have those dimensions exactly. Perhaps you can get it with some calculations.
750663
 

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I have that frame diagram just not quite sure how i would get that measurement from it
The diagram shows that the floor pan is 54.75" wide at that point. The floor supports are 30" center-to-center, 54.75" - 30" = 24.75". 24.75" / 2 = 12.375". So the distance from the center of each floor support to the edge of the floor pan should be 12-3/8".
 

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The diagram shows that the floor pan is 54.75" wide at that point. The floor supports are 30" center-to-center, 54.75" - 30" = 24.75". 24.75" / 2 = 12.375". So the distance from the center of each floor support to the edge of the floor pan should be 12-3/8".
So they are supposed to be perfectly centered? Okay that’s what i needed to know thanks
 
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