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It is said that you cannot determine the gear ratio (beyond tags or numbers) for an open rear end. You can with limited slip easily but I got to thinking (kinda hurts yaknow?) that why wouldn't it be the number of turns of the yoke to make the sum of both wheels = 1 revolution. Is there something about the spider gears when one wheel is stopped that makes it not work out?
 

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Never heard that one about an open rear. The ring and pinion are always meshed so if the pig is out of the car, count the teeth.

The spider gears are there only to direct the power to either 1 wheel or the other, depending on which is "free'er" to spin at the moment.

The proper way in the car would be to hold one wheel stationary (leave it on the ground) and marking the raised tire/wheel somewhere where you can watch for a single revolution. Then count the # of pinion rotations needed for 1 wheel rotation. Since 1 wheel can't rotate, the spider gears will ONLY transfer the rotation to the single wheel. There is no where else for the rotational motion to go.

If your are up on your math fractions it will give an accurate representation of the gear ratio. No additional computations are needed.
 

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Yeah, I have done exactly what Dennis is saying to verify before. May not get EXACTLY....2.79 works out to about 2.8 but you get the idea.
 
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