For those of you who have read my previous posts about my high rpm skip, and the solution, this is an extention of that.
(Basic idea of previous posts was that the original ignition in my 66 only provided 8 volts to the coil, which was not enough to run the MSD with malfunction.)
My idea is to bypass the resistor wire by running a new piece of wire from the key side of the ignition to the other side of the harness where the wires to the coil and solenoid are connected.
From the shop manual, and searching under the dash with a flashlight, I have determined that the resistor wire is the fat pink wire that runs from the key side of the ignition to the side of the harness inside the car, and on the firewall. This is labeled 16A in the shop manual.
On the other side of the harness, (firewall, inside engine bay) two wires stem out from the post where 16A is connected to, wire 262, which goes to the (I) post on the starter solenoid, and wire 16/16B, which runs to the positive side of the coil.
Currently, I have a wire which runs from the key side of the ignition switch, to an external relay, which is connected to the battery, and then flips over allowing juice to the coil when the key is turned on.
What I want to do is bypass the resistor wire by running from the key side of the ignition and then connecting it to wires 262 and 16/16B.
My first question then is there a full 12V on the key side of the ignition?
If so, does anyone see any other reasons why this would not work to get 12V to the coil?
A mustang guy I work with frequently said that the starter soleniod may get burned out by running the higher voltage through the I post all the time, is this a possibility?
Thanks for any suggestions.
Dave
(Basic idea of previous posts was that the original ignition in my 66 only provided 8 volts to the coil, which was not enough to run the MSD with malfunction.)
My idea is to bypass the resistor wire by running a new piece of wire from the key side of the ignition to the other side of the harness where the wires to the coil and solenoid are connected.
From the shop manual, and searching under the dash with a flashlight, I have determined that the resistor wire is the fat pink wire that runs from the key side of the ignition to the side of the harness inside the car, and on the firewall. This is labeled 16A in the shop manual.
On the other side of the harness, (firewall, inside engine bay) two wires stem out from the post where 16A is connected to, wire 262, which goes to the (I) post on the starter solenoid, and wire 16/16B, which runs to the positive side of the coil.
Currently, I have a wire which runs from the key side of the ignition switch, to an external relay, which is connected to the battery, and then flips over allowing juice to the coil when the key is turned on.
What I want to do is bypass the resistor wire by running from the key side of the ignition and then connecting it to wires 262 and 16/16B.
My first question then is there a full 12V on the key side of the ignition?
If so, does anyone see any other reasons why this would not work to get 12V to the coil?
A mustang guy I work with frequently said that the starter soleniod may get burned out by running the higher voltage through the I post all the time, is this a possibility?
Thanks for any suggestions.
Dave